Thursday, January 17, 2013

Direction of Upthrust

Introduction to direction for upthrust

As we know that the substance floats in a liquid whose density is less than the density of the liquid in which the substance is submerged. On the other hand, the substance sinks in a liquid whose density is more than the density of liquid in which the substance is submerged. For example, wood floats on water but iron block sinks in the water, because the density of wood is less than the water but the density of iron is more than the water. To understand this concept first we introduce the term upthrust and buoyancy. Having problem with Optical Density Formula keep reading my upcoming posts, i will try to help you.

Direction of Upthrust

If a body immersed completely or partly in a liquid, there is a loss in the weight of the body. The property of a liquid due to which the body loses its weight in the liquid, is called buoyancy. If we immersed a body in a liquid, there is some upward force acting on the body. S that the net force due to gravity on the body = weight of the body in air – upward force acting on the body. Thus, the body loses some weight. The upward force exerted by the liquid on a body, which is immersed in the liquid, is known as the upthrust force or the buoyant force. The direction of the upthrust force is always upwards, which can be proved by a physical activity. I have recently faced lot of problem while learning All Physics Formulas, But thank to online resources of math which helped me to learn myself easily on net.

Activity for the Direction of Upthrust

Consider a beaker filled with a liquid of density d. Let a block of height h is immersed in the liquid. Now the pressure at face A is P1 and the pressure at face B is P2.

So, as we know that the pressure is equal to the product of height, density of the liquid and the acceleration due to gravity.

P1 = h1 × d × g = h1dg              (directed downwards)

P2 = h2 × d × g = h2dg              (directed upwards)

Net pressure , P = P2 – P1 = h2dg – h1dg = (h2 – h1)dg

P = hdg            (directed upwards)

So, force = pressure × Area

F = hdg × A

F = Vdg                       (height × Area = Volume)

This is the upthrust force acting upwards.


Conclusion

From the above discussions, we can conclude that the direction of upthrust is directed upwards. The upthrust force depends on the volume of the body immersed and the density of the liquid in which the body immersed.

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