Solve Online Velocity

Introduction to solve velocity online :

Define Velocity :

Velocity of a body is distance travelled by it per unit time in given direction .It is given as

Velocity = `(Distance )/(Time taken)`

v = `(s)/(t)`, where v is velocity , s is distance travelled in given time in given direction, t is time taken

Velocity = `(displacement)/(time taken)` = `(s)/(t)`  = v

where v is velocity , s is displacement , t is time taken.

The SI unit of velocity is the same as speed , namely, metres per second ( ms-1 or `(m)/(s)` )

Average Velocity :

Average velocity is the total displacement over total time taken.

Average velocity = `(t otal *displacement)/(t otal * time * taken)`

Note :

Speed and velocity are not always equal in magnitude.

The magnitude of speed and velocity of a moving body is equal only if the body moves in a single straight line.
But if a body does not move in  a single straight line , then speed and velocity of the body are not equal.
Average speed of a moving body can never be zero but the average velocity of a moving body can be zero.

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Solve problems based on velocity online


Lets solve problems on velocity online :

1) A car travels a distance of 200 km from Delhi to Ambala towards North in 5 hours. Calculate (i) speed and (ii)velocity of car  for the journey.

Solution : (i) Speed = `(distance )/(time taken)`  = `(200 km)/(5 h)`  = 40 `(km)/(h)`

(ii) Velocity = `(displacement )/(time taken)`  = `(200 km)/(5 h)`  = 40 `(km)/(h)`  towards North



2) A car travels 10 km in 4 hours in the North direction , find the velocity.

Solution :Velocity = `(displacement )/(time taken)`  = `(100 km)/(4 h)`  = 25 `(km)/(h)`  towards North

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Solve problem based on average velocity online : (continued)


Lets solve online some problems based on average velocity

1) A boy runs 100 metres in 50 seconds in going from his home to the shop in the East direction, and then runs a distance of 100 metres again in 50 seconds in the reverse direction from shop to reach home.Calculate (i) average speed (ii) average velocity.

Solution : (i) Average speed = `(t otal * d istance* travel ed)/(t otal *time* taken)` =  `(100 +100)/(50 +50)` = `(200)/(100)` = 2 `(m)/(s)`

(ii) Average velocity =  `(t otal * displacement)/(t otal *time *taken)`

The boys runs East 100 m and then 100m in opposite direction( towards West ) .

Total displacement = 100m - 100m = 0m

Total time taken = 50 sec + 50 sec = 100 sec

Average velocity = `(0)/(100)` = 0 `(m)/(s)`